**Work Hours**Monday to Friday: 7AM - 7PM

Weekend: 10AM - 5PM

**Assumptions for Example**

- There are 2 types of bars in one way slab: Main Bar & Distribution Bar
- Main Bar Diameter = 10 mm
- Spacing Between Main Bars(C/C distance) = 150 mm
- Distribution Bar Diameter = 8 mm
- Spacing Between Distribution Bars(C/C distance) = 100 mm
- Length of Slab = 6000 mm
- Width of Slab = 3000 mm
- Width of Beam of Slab = 300
- Concrete Cover = 25 mm
- Slab Thickness = 150 mm
- We are using Steel grade of fe500

**Calculation Procedure**

**Step 1: Calculation of total no. of bars**

Calculate the number of bars required (main and distribution both).

Number of Main Bars = (Length of Longer Side / Spacing) + 1

=(( 6000/150)+1) = 41

Number of Distribution Bars = (Length of Shorter Side / Spacing) + 1

= ((3000/100)+1) = 31**Step 2: Calculation of cutting length of main & distribution bar**

Cutting Length of Main Bar = Clear Span (L) + (2 x Beam Width) – (2 x Con. Cover) + (1 x Inclined Length) – (45° bend x 2)*where L = Clear Span of the Slab ;0.42D = Inclined length (Bend length) ;1d = 45° bends (d is diameter of bar)*

First calculate the length of “D“. i.e D = (Thickness) – 2 (Clear cover at Top, Bottom) – Diameter of the bar.

D = 150- 2×25 – 10 = 90 mm

Cutting Length of Main Bar = 3000 – 2×300 – 2×50 + 0.42×90 – 2×10= 2318 mm

Cutting Length of Distribution Bar = Clear Span (Lclear) – (2 x Con. Cover)

= 6000 – 2×25 = 5950 mm**Step 3: Calculation of Top Distribution Bar**

Numbers of Top distribution bar for longer span = {(L/4)/spacing + 1} × 2 sides

= ((3000/4)/100 +1) = 9

Cutting Length of Top Distribution Bar = Clear Span – (2 x Con. Cover)= 5950 mm**Step 4: Total Length Calculation**

Total Length of Main Bar = 41 x 2318 = 95038 mm = 95.038 m

Total Length of Distribution Bar = 31 x 5950 + 9 x 5950 = 238000 mm = 238 m**Step 5: Calculation of Steel Weight**

Weight of the bar as per their length and diameter by following Formula: –

Unit weight formula for kg per metre =(D^2/163) × L kg/m

Unit weight for feet per metre = (D^2 / 533) × L kg/ft

L is the required length of Steel bar of Diameter D

Weight of Main Bar = (102/163) x 95.038 = 58.31 Kg

Weight of Distribution Bar = (82/163) x 238 = 93.45 Kg

**Final Result**

**Total Steel Weight = 58.31 + 93.45 = 151.76 Kg**

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