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**Assumptions for Example**

- There are 2 types of bars in a Beam: Main Bar & Distribution Bar
- Main(Top) Bar Diameter = 16 mm
- Number of Main(Top) Bars = 3
- Distribution(Bottom) Bar Diameter = 20 mm
- Number of Distribution(Bottom) Bars = 3
- Length of Beam = 4500 mm
- Width of Beam = 230 mm
- Depth of Beam = 600 mm
- Diameter of Stirrup(Ring) = 8 mm
- C/C distance of ring(mm) at supports= 100 mm
- C/C distance of ring(mm) at mid supports= 150 mm
- Concrete Cover = 25 mm
- We are using Steel grade of fe500

**Calculation Procedure**

**Step 1: Calculation of cutting length for Main(Top) & Distribution(Bottom) Bar’s**

Cutting Length of Main Bar = Length + Development Length(on 2 sides) – Bend(on 2 ends) – clear cover

Cutting Length of Distribution Bar = Length + Development Length(on 2 sides) – Bend(on 2 ends) – clear cover

Here , Development Length = 50D & Bend =2D ; where D= Diameter of Bar

Cutting Length of Main Bar = 4500 + 2x50x16 – 2x2x16 – 2×25

= 5986 mm

Cutting Length of Distribution Bar = 4500 + 2x50x20 – 2x2x20 – 2×25

= 6370 mm

**Step 2: Calculate number of stirrup**

Number of Stirrups required = 2xStirrup(support zone) + Stirrup(mid support zone)

= 2[(L/3)/spacing at support + 1] + [(L/3)/spacing at mid support + 1]

= 2[(4500/3)/100 + 1] + [(4500/3)/150 + 1]

= 43

**Step 3: Calculate cutting Length of Stirrup**

Cutting length of Stirrup = Perimeter of stirrup + Number of Bends + Number of Hooks

= 2(a+b) + 3 numbers of 90 degree bends + 2 numbers of hooks

= 2(a+b) + 3x2xd + 2x2xd

Here, a & b are Width & Depth of beam ; d is the diameter of stirrup

Cutting length of stirrup = 2(230 + 600) + 3x2x8 + 2x2x8

= 1740 mm

**Step 4: Total Length Calculation**

Total Length of Main(top) Bar = 3 x 5986

= 17958 mm = 18 m

Total Length of Distribution(bottom) Bar = 3 x 6370

= 19110 mm = 20 m

Total Length of Stirrup Bar = 43 x 1740

= 74820 mm = 75 m

**Step 5: Calculation of Steel Weight**Weight of the bar as per their length and diameter by following Formula: –

Unit weight formula for kg per metre =(D2/163) × L kg/m

Unit weight for feet per metre = (D2/ 533) × L kg/ft

L is the required length of Steel bar of Diameter D

Weight of Main Bar = (162/163) x 18 = 28.27 Kg

Weight of Distribution Bar = (202/163) x 20 = 40.08 Kg

Weight of Stirrup Bar = (82/163) x 75 = 29.45 Kg

**Final Result**

** Total Steel Weight = 28.27 + 40.08 + 29.45 = 97.8kg**

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